小红的子串权值和【Python和C++实现】 n = int(input.strip)s = input.striptotal_substrings = n * (n + 1) // 2ans = total_substringsfor i in range(n - 1): if s[i] != s[i python cin 子串 ans 子串权值 2025-08-05 19:41 4