摘要：The √X order sub-levelof the even midpointX, and the even midpointX, its position in the end order all digit field, jointly determ

Section 2, [Conjecture Research] Conclusion:

The √X order sub-level of the even midpoint X , and the even midpoint X , its position in the end order all digit field, jointly determines the number of inverse high-shrink fgsx orders of the even number , and the position and number of inverse high-shrink fgsx cut point G. At the same time, it is also determining the solution containing the [conjecture] and the minimum number. As the prime order sx of the order continues to increase. While ensuring that the minimum number of solutions of [conjecture] continues to increase, in the same order number field, it affects each even number in the same order number field, and contains the minimum number of solutions. As a result, even numbers in the same order field contain solutions of [conjecture], and the minimum number is also different.

From the order full fraction evaluation formula of even number [Conjecture], the inference result has been obtained from its various unknown relationships: "The highest total fraction value of any even order is ≥ its ny value."

( Conclusion of Chapter 5 of "The Next Chapter" 8, )

Because, ny ≥1 is a natural number.

According to the following article, Chapter 5,

“Conclusion 17:

Any even number with a full formula, their highest full formula value, and their end point segment fractional value, are both ≥2, and have at least 2 sets of [conjecture] solutions. ”

To conclude,

The highest total fraction value of any even-order equation is ≥1 and has at least a set of integer [conjecture] solutions;

The sum of any even-numbered total fractional value and its end point segment fractional value is ≥2, and there are at least 2 sets of [conjecture] solutions.

Among natural numbers, even numbers with orders are proved to be of equality, and their [conjecture] are valid. They contain the minimum number of [conjecture] solutions, all of which are: ≥2 groups. And with the midpoint X of the even number, the order level of the order number field increases and continues to increase.

Therefore, it is concluded:

"The Next Chapter", six chapters,

Conclusion 1.

"The larger the even numbers in natural numbers, the higher the √X sub-level of their midpoint X, and the more fractions they form: ≥1. The minimum number of solutions containing [conjecture] for all kinds of even numbers also increase with the order level X of even numbers, and the number of ny values ​is continuously increasing with the ny value as the step jumping method."

Because the highest total fraction of even numbers and its end point fraction, they are just two fractions in the order of even numbers and each of the added fractions. Moreover, the values ​​of each incremental score of the order form have no negative values. Therefore, as long as the even order form has a full fraction, its highest full fraction will have a solution to [conjecture]: ≥1 group; its highest full fraction, and its end point segment fraction, the number of solutions to the [conjecture] of the two fractions: both are ≥2 groups.

The highest total fraction of even numbers and its end fraction, both fractions have at least ≥2 [ conjecture] solutions . It has been fully proved that even numbers already have solutions to [conjecture], their [conjecture] is already established and is multi-solution.

So I got it

In natural numbers,

The solution to even numbers [conjecture] contains the minimum number of evaluation formulas:

Pfc*1/sx (*dxs )*qxz cum *fgsx cum -ny

=2ny+[2nysx(ny-1)+2(ny)^2(2ny-1) ]/sx(sx+2ny)}*qxz Tired *fgsTiredx-ny

It accurately reflects that the even number and its [conjecture] solution contain the change relationship between the minimum number.

The formula fully proves that

Among natural numbers, all even numbers (≥18) with order full equations have at least 1 [conjecture] solution.

Their highest total fraction, together with their end point fraction, and the sum of the two fraction values, exists: ≥2 sets of [conjecture] solutions.

Because the highest total fraction and the end point segment fraction are just two order fractions in the even number [conjecture] order, they are only part of each order fraction. The order of each order of the order is added to the score, and they are generated without negative values.

It is fully proved that in natural numbers, any even numbers ≥18 have their [Goldbach conjecture]. And they all exist: ≥2 groups of multiple solutions.

The full text of "[Conjecture] Research" and "The Next Article" ends.

Thanks for reading!

Welcome to participate in the discussion!

See you next week!

来源：科学屎壳郎