摘要：The reverse reduction coefficient fxsx, after entering the reverse number axis segment, theyall become the reverse high reduction

"Chapter 5"

Section 4,

In the highest total fraction, the number and function of anti-high shrinkage fgsx orders

Section 4 1.

In the highest total fraction, the position and number of the anti-high shrinkage fgsx order

The reverse reduction coefficient fxsx , after entering the reverse number axis segment, they all become the reverse high reduction order fgsx reduction.

In the calculation of the highest full-form fraction , its inverse reduction coefficient fxsx all becomes the inverse high-order reduction fgsx reduction .

Figure 1.

If we put the fields of each order on the even positive and negative bidirectional number axis segments , starting from the highest full form ,

Use, a, b , c , d ,..., to express,

The parts after the stage above the end stage are all anti-high shrinkage fgsx order reduction coefficients.

The role of anti-high shrinkage fgsx order is an important factor in the calculation of the highest total fraction and the end segment fraction .

There are two functions of anti-high shrinkage fgsx order :

One is only the reduction effect of anti-high shrinkage fgsx order ;

The other is that, while having a shrinking effect, its first odd sum number 1, the anti-high shrinkage fgsx formed by it also has a cutting effect on the relevant fraction .

View 1 ,

.01^2..3^2....5^2......(sX)^2........(√X)^2....X

2X..(√2X)2...................fgs2..........fgs1...X

In the calculation of the highest full-form fraction , some even numbers have anti-high shrinkage fgsx order entered into the calculation.

As shown in the figure above , fgs1 is the anti-high shrinkage fgsx order across the vertical columns and in the same position of the end segment.

Due to different even - numbered midpoints​​​

In the calculation of the highest total fraction,

It is necessary to first determine the position and quantity of the inverted high-shrinking fgsx order between vertical columns and in the same position in its order number field on the inverse number axis segment . The specific calculation can only be carried out after the effect of the inverse high-contraction fgsx order on the highest total fraction is clearly calculated.

Therefore, we make the highest total fraction of an even number, with and without the existence of cutting points, and inversely shrink the fgsx order , as shown in the simplified diagram .

The highest full-form fraction, with or without cutting points, inversely shrinks the fgsx order , schematic diagram:

Illustration,

Since the midpoint​​​​

In the picture,

Lowercase: a, b , c , d , e , f , g , ...,

Respectively, the endpoint of the order field is also the anti-high-shrinking fgsx cutting point G point;

Capital letters: A, ( B1 + B2 ) = B , C , D , E , F , ...,

Represent their full order fields respectively .

C、D、E、F、……，

They are their anti-high shrinkage fgsx order fields respectively .

A: It is the numerical field of the highest full-form fraction .

( B1 + B2 ) = B : It is the full degree field of the end point order .

B1 is the end number field , which is the reduced part of the end stage that can form an anti-high-shrinking stage .

B2 is the reverse high-shrink fgsx stage reduction part of the full stage of the end point .

In the picture,

Between the longitudinal columns, at the same position , corresponding to the forward section A is the anti-high contraction fgsx cutting point G in the highest full-form fraction ;

Between the vertical columns, in the same position, corresponding to the forward B1 segment is the non-cutting point of the highest full-form fraction, the reverse high-reduction fgsx order reduction factor part.

On an even-numbered positive and negative bidirectional number axis segment,

The numerical field with the highest full form : In paragraph A ,

Between the vertical columns, the number of the endpoints of the anti-high-shrinking fgsx order field on the same position: c , d , e , f , g , ... is the position and number of the anti-high-shrinking fgsx cutting point G of segment A. ;

In the B1 section of the terminal stage ,

Between vertical columns, the number of segments containing the anti-high shrinkage fgsx order field in the same position: C , D , E , F , G ,...,

It is the position and number of the highest full-form anti-high shrinkage fgsx order reduction factor.

As the order increases step by step , the number of fxsx factors decreases intermittently. After exceeding the order of the end point ( √ factor .

The end stage stage fraction has the least number of fgsx , sometimes none.

The cumulative reduction rate of the anti-high shrinkage fgsx order at the end section is the smallest .

Among the various full-form fractions, the highest full-form fraction has the smallest anti-high shrinkage fgsx order reduction factor and the smallest reduction accumulation, and some even numbers may even have none.

All anti-high shrinkage fgsx orders , like the reverse reduction coefficient fxsx , have a one-way reduction effect. Only the first odd-sum number 1 at the beginning of the anti-high-shrinking fgsx order , and the anti-high-shrinking fgsx itself, can divide the corresponding order and have the function of cutting at the same time .

The higher the order , the larger the prime order of the order : sx , the larger the order field formed . Since the lengths of the two number axes in both directions are equal, their absolute values ​​are equal . Even midpoints X, numbers higher than 3rd order, have fewer reverse orders than forward orders.

Since the number of orders contained in the forward direction is equal to the number of order fractions ,

It follows that

"Part Two", Chapter Five, Presumption 3,

For any even-numbered order formula, the number of reduction factors of the anti-high-scaling fgsx order and the number of its anti-high-scaling fgsx cutting points are less than the number of its order fractions. It is certain that any even number of order formulas have fractions that are not cut by anti-high shrinkage fgsx .

Section 4 2.

sx , and n y values, are the main factors that determine the size of the numerical field, the value of the single factor qxz , and the value of the single factor fgsx .

In order to facilitate the size comparison between each order number field , the order square difference is deformed as follows.

Transform the square difference expression of the order field into:

[(sx+2ny)^2-(sx)^2]/2

=[2sx +2ny ]2ny/2

=2sx*ny +2(ny)2

=2ny(sx +ny)

In square difference : 2ny (sx +ny) ,

2ny is the multiplication factor of (sx +ny) .

It follows that

"Part Two", Chapter Five, Presumption 4,

Among the two factors, s x and ny , that determine the size of the order magnitude field , the ny value is the weight factor that determines the size of the square difference field .

For example,

For ny =1 of order 29 , its square difference field is:

2ny (sx +ny)

=2*1*(29+1)

=60

And the 19th order field, which is 2 orders lower than him , because ny =2

2ny (sx +ny)

=2*2*(19+2)

=84

Although the 19th level is 2 levels lower than the 29th level .

Because ny =2 of order 19 is greater than ny =1 of order 29 ,

As a result, the low-level 19th level was actually larger than the 29th level , which was two levels higher than him .

Their difference is: 84-60=24 odd bit units.

It can be seen from the above calculation that

In the order field [( sx +ny)^2 -( sx)^2 ]/2=2ny(sx +ny) ,

The weight of n y value is much larger than that of sx .

Finished writing.

Thanks for reading!

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来源：邃若水