摘要：res = pattern.sub(lambda match:dx.get(match.group(1), match.group(1)), p)

def rep(p, k):

dx = {format(i, 'b'):k[i] for i in range(len(k))}

print(dx)

res = pattern.sub(lambda match:dx.get(match.group(1), match.group(1)), p)

print(res)

return res

p = "10://0.11.111-110"

k = 'quan|fan|zhang|rong|yi|wen|chen|jun'.split('|')

rep(p, k)

来源：罗罗学英语